๐ŸŽฏ Try it

Single choice

Expand โˆ’2(xโˆ’4)-2(x - 4).

๐Ÿ“ Start with the mistake

Work on paper; compare each line with the explanation before trying the next problem.

Distribution: A learner writes 3(x+4)=3x+43(x + 4) = 3x + 4. Both terms inside the bracket must be multiplied: 3x+123x + 12. Try 2(xโˆ’5)2(x - 5), then โˆ’2(x+3)-2(x + 3). Answers: 2xโˆ’102x - 10; โˆ’2xโˆ’6-2x - 6.

Combining terms: 3x+2x=5x3x + 2x = 5x, but 3x+23x + 2 cannot become 5x5x. Only like terms combine. Simplify 4a+3โˆ’a+54a + 3 - a + 5: 3a+83a + 8.

Equation balance: For 5xโˆ’7=185x - 7 = 18, add 7 to both sides, then divide by 5. x=5x = 5; substitution gives 25โˆ’7=1825 - 7 = 18.

Sign check: โˆ’3x=12-3x = 12 gives x=โˆ’4x = -4. Dividing by a negative changes the sign of a positive quotient.

โœ๏ธ Mixed practice

  • 1.
    Expand 4(2xโˆ’3)4(2x - 3).
  • 2.
    Simplify 7yโˆ’2+3y+67y - 2 + 3y + 6.
  • 3.
    Solve 2x+9=12x + 9 = 1. Check the sign by substitution.
  • 4.
    Solve 3x+2=x+103x + 2 = x + 10.
  • 5.
    A learner writes โˆ’2(xโˆ’3)=โˆ’2xโˆ’6-2(x - 3) = -2x - 6. Identify the first error.
  • 6.
    Solve 5โˆ’2x=115 - 2x = 11, then check in the original equation.
  • ๐Ÿ”‘ Worked corrections

  • 1.
    8xโˆ’128x - 12: distribute 4 to both terms.
  • 2.
    10y+410y + 4: combine yy terms separately from constants.
  • 3.
    x=โˆ’4x = -4: subtract 9 to get 2x=โˆ’82x = -8; 2(โˆ’4)+9=12(-4) + 9 = 1.
  • 4.
    x=4x = 4: subtract xx and 2 from both sides to get 2x=82x = 8.
  • 5.
    The second product is positive: (โˆ’2)(โˆ’3)=6(-2)(-3) = 6, so โˆ’2x+6-2x + 6.
  • 6.
    x=โˆ’3x = -3: subtract 5, then divide by โˆ’2-2; 5โˆ’2(โˆ’3)=115 - 2(-3) = 11.
  • โœ… Check your understanding

    Single choice

    Solve 4x+1=134x + 1 = 13.